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Sunday, April 15, 2018

Today's Answer



ANSWER: 2+3+(3 x11) = 38

Look closely. at the last line.

The clock is on a different time. There are not 4 bananas there are 3. The square is missing inside the pentagram and hexagon.

16 comments:

Anonymous said...

Are you sure of this answer? It looks to me that the bananas are worth the number 4 and the hexaspheres are worth 15. My answer is 66

Anonymous said...

Wow, we are a bunch of dummies. 106 comments and only 5 correct answers. Must have been a bunch of obama voters.

Anonymous said...

How is the hex minus the square not worth 10? three fives is fifteen. There is no number doubled that makes eleven. Maybe 11:24 can enlighten me.

Anonymous said...

well, I was at 165 until I read the number of bananas and missing square... let me re-figure...

Anonymous said...

38

Anonymous said...

Ha! Just saw you had the answer there. I go directly to the challenge. LOL

Anonymous said...

11:24, I didn't vote for that turd, but I am dummer than a nit. I had 23

Anonymous said...

7:21 Count the sides...you obummer voter

Anonymous said...

7:21 The 3 symbols that equal 45 are 15 each because they contain 15 sides. A square is 4 sides + a pentagram is 5 sides + a hexagon is 6 sides. 4+5+6=15. In the bottom equation the symbol is missing the square(5+6=11 or 15-4=11) that is how you get the number 11.

By the way I had the wrong answer too because I didn't pay attention to the problem. I along with over 100 other people made incorrect assumptions and didn't pay attention. Something we are all guilty of. The puzzle was a great life lesson.

Anonymous said...

I call BS on this one. No math professor would buy that "equation." You can't just put the operands anywhere, willy-nilly. It is not mathematically correct, as answered.

Anonymous said...

9:57
There are only 3 bananas in the last line NOT 4. Count the sides of the square, hexagon and pentagram. That is 15. Take away the 4 sides for the square and that leaves 11.

7:21
See above :)

Anonymous said...

957, the bananas were worth 4 when there WERE 4 bananas. There are 2 groups of 3 bananas in the final equation. Your answer is wrong.

721, count the total number of sides, Einstein.

Anonymous said...

9:57
There are 2 sets of 3 bananas. NOT 4 like the lines 2 and 3.

My answer was correct. After all I sent this to Joe :)

Anonymous said...

Thanks, 8:17, I see that now. Funny how we make assumptions that misguide ourselves. Thanks for your input.

Anonymous said...


This is an Order of Operations problem, not how many bananas or is the clock showing a.m or p.m. problem.

Anonymous said...

Order of Operations? Wow, its been a long time since I heard that terminology.

Great puzzle!