Donald J. Trump has opened a wide lead in Maryland, according to a new poll that shows the leading Republican presidential candidate poised to sweep the state’s delegates later this month.
A survey from the Monmouth University Polling Institute released on Wednesday finds that Mr. Trump has the support of 47 percent of likely Republican primary voters in Maryland. He is trailed by Gov. John Kasich of Ohio, who has 27 percent, and Senator Ted Cruz of Texas, with 19 percent.
Mr. Trump’s support in Maryland is fueled largely by men who do not have college educations. He also does well with “very conservative” votes while splitting the moderate vote with Mr. Kasich.
“If Trump’s current level of support translates to each of Maryland’s eight congressional districts, he may be able to run the table in the all-important delegate contest,” said Patrick Murray, director of the Monmouth group.
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7 comments:
I'm guessing the Kasich supporters are true Anti-Trump people - since Kasich is mathematically eliminated already!
Do not vote for Julie Brewington. She is online begging people to vote for her as a Delegate and she is viciously attacking Cruz supporters. She is also begging for people to give HER a building so she can have a Cruz Headquarters. She is a Cruz Loser!
P.S. Don't vote for Bonnie Luna either.
12:56 - thanks for the info...I knew about Julie the Stoolie!
Vote for the person shown as a Trump delegate... Not uncommitted.
Good. I hope Trump is the Republican nominee.
Pretty much sums up the eastern shore - "Mr. Trump’s support in Maryland is fueled largely by men who do not have college educations." They still have not figured out their votes don't count in MD.
Whoever Julie is,she must be a local hero.
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